1+sinx*cos2x=sinx+cos2x

1+sinx (cos^2 x — sin^2 x)=sin x+cos^2 x — sin^2 x1+sin x cos^2 x-sin^3 x=sinx (1 — sinx)+cos^2 x1 — sin^3 x — sin x (1-sinx)=cos^2 x — sin x*cos^2 x 1 — sin^3 x=cos^2 x (1-sinx)+sinx*(1-sin x) (1-sin x) (1+sinx+sin^2 x)=(cos^2 x+sin x) (1-sin x) 1+sinx+sin^2 x=cos^2 x+sin x1=cos 2x2x=0x=0Ответx=2pi*n; n прин z