2b / 2b+3+5/3-2b — 4b^2+9/4b^2-9

=1+3+\frac{5}{3-2b}-4b^{2}+\frac{9}{4b^{2}-9}-9=-\frac{5}{2b-3}+\frac{9}{ (2b-3) (2b+3) }+4-4b^{2}=\frac{-6-10b-20b^{2}+45-16b^{4}+36b^{2}}{4b^{2}-9}=-\frac{16b^{4}+20b^{2}+10b-75}{4b^{2}-9}