2sinx-√3tgx-2√3cosx+3=0 решить уравнение

2sinx -√3 tgx — 2√3 cosx+3=02sinxcosx-sqrt (3) sinx-2sqrt (3)*cos^2x+3cosx=0sinx (2cosx-sqrt (3) -cosx*sqrt (3) (2cosx-sqrt (3)=0 (2cosx-sqrt (3) (sinx-cosx*sqrt (3)=0cosx=sqrt (3) /2 sinx-sqrt (3) cosx=0 tgx=sqrt (3) x=+-П/6+2Пk x=П/3+ Пk