А) sin (x-П/3)*cos (х-П/6)=1 б) sin x/2*sin 3x/2=1/2 в) 2sin (П\4+ х)*sin (П/4-х)+sin^2x=0

a) 1/2 (sin (x-p/3+x-p/6)+sin (x-p/3-x+p/6)=1-sin (p/2-2x) -sinp/3=2- (cos2x+sqrt (3) /2)=2cos2x=(-4-sqrt (3) /2 (-4-sqrt (3) /2<-1 => нет корнейb) 1/2 (cos (x/2-3x/2) -cos (x/2+3x/2)=1/2cosx-cos2x=1cosx-2cos^2x=0cosx (1-2cosx)=0[x=p/2+pn[x=+/-p/6+2pnc) cos2x+sin^2x=01-2sin^2x+sin^2x=01-sin^2x=0 (2-1+cos2x) /2=0cos2x=-12x=p+2pnx=p/2+pn