(n+2) / (n^2-n-6) -n/ (n^2-6+9)*(2n-6) ^2

Будем считать что там n пропущено в знаменателеn+2) / (n^2-n-6) -n/ (n^2-6n+9)*(2n-6) ^21. (n+2) / (n^2-n-6)=(n+2) / (n-3) (n+2) [n^2-n-6=0; n1=3; n2=-2 по т. Виета]2. n/ (n^2-6n+9)=n/ (n-3) ^2) 3. (n+2) / (n^2-n-6) -n/ (n^2-6n+9)=(n+2) / (n-3) (n+2) -n/ (n-3) ^2)=(n+2) (n-3) -n (n+2) / (n-3) ^2 (n+2)=(n+2) (n-3-n) / (n-3) ^2 (n+2)=(-3) / (n-3) ^2) 4. (-3) / (n-3) ^2)*(2n-6) ^2=(-3) / (n-3) ^2)*4*(n-3) ^2=-3*4=-12Отв. -12