Найдите наибольшее значение функции y=(x+4) (x-2) в квадрате) -22 на отрезке [-4; 3]

y=(x+4) ⋅ (x-2) 2-22ПРОИЗВОДНАЯy'=(x-2) 2+(x+4) ⋅2⋅ (x-2)=(x-2) ⋅ (x-2+2x+8)=(x-2) ⋅ (3x+6)=3⋅ (x-2) ⋅ (x+2) => y'=0 => x1=2, x1∈[-4; 3] x2=-2, x2∈[-4; 3]y (2)=-22 y (-4)=-22y (3)=-15y (-2)=10ОТВЕТ: 10