Помогите решить! (sin5x — sin3x) / (2cos4x)=sinx

sin5x — sin3x=2 sin (5x-3x) /2*cos (5x+3x) /2=2 sin4x cos4x2 sin4x cos4x/ (2cos4x)=sinx sin4x=sinx Ответx=πn, n ϵ Zx=2πn -π/5 , n ϵ Zx=2πn+π/5 , n ϵ Zx=2πn -3π/5 , n ϵ Zx=2πn+3π/5 , n ϵ Zx=2πn -2π/3 , n ϵ Zx=2πn+2π/3 , n ϵ Z