Приведите уравнения к виду.ax^2+bx+c=0 x (3x+5) -1=x (x-4) (7x-1) (2+x)=(x-4) (x+4) (6+x) ^2=(x-2) (3-x) x (8-3x)=(5x-1) ^2

1) x (3x+5) -1=x (x-4) 3x^2+5 х-1=x^2-4x3x^2+5x-1-x^2+4x=02x^2+9x-1=0 2) (7x-1) (2+x)=(x-4) 14x+7x^2-2-x=x-413x+7x^2-2-x+4=07x^2+12x+2=0 3) (x+4) (6+x) ^2=(x-2) (3-x) (x+4) (36+12x+x^2)=3x-x^2-6+2x36x+12x^2+x^3+144+48+4x^2-3x+x^2+6-2x=0x^3+17x^2+30x+198=04) x (8-3x)=(5x-1) ^28x-3x^2=25x^2-10x+18x-3x^2-25x^2+10x-1=0-28x^2+18x-1=0 умножаем на -128x^2-18x+1=0