Решите систему уравнений! {10- (9x-2y)=18-4y} {2x-3 (1+y)=2 (3x-y) } любым способом!

10- (9x-2y)=18-4y2x-3 (1+y)=2 (3x-y) 2x-3 (1+y)=2 (3x-y) 2x-3-3y-6x+2y=0-4x-3-y=0y=-4x-3 10- (9x-2y)=18-4y10-9x+2y-18+4y=0-8-9x+6y=0-8-9x+6*(-4x-3)=0-8-9x-24x-18=0-26-33x=0x=-26/33 -4*(-26/33) -3-y=0104/33-3-y=0y=5/33