log3 (2x+1)=2; log0,2 (x^2+4x)=-1; log2 5 (x) -log5 (x) -2=0; log1/3 (x^2-5x+7) >0;

1) log3 (2x+1)=22x+1=92x=8x=4 2) log0,2 (x^2+4x)=-1x^2+4x=2x^2+4x — 2=0x1=V6 — 2x2=- (V6+2) 3) log^2 5 (X) — log5 (x) -2=0 (log5 (X) -2) (log5 (x)+1)=0x1=25x2=1/5 4) log1/3 (x^2-5x+7) >0x^2-5x+7>1x^2-5x+6>0 (x-6) (x+1) >0x1>6x2>-1