Решить уравнение с параметром. |2x+1| — |x|=5a

x=0x=-1/2x>=02x+1-x=5ax=5a-1 5a-1>0 a>1/5x <= -1/2-2x-1+x=5a-x-1=5ax=-1-5a- (5a+1) <-1/2 5a+1>1/2 5a>-1/2 a>-1/10 (-1/2; 0) 2x+1+x=5a3x=5a-1x=(5a-1) /35a-1<0 a<1/5 5a-1>-3/2 5a>-1/2 a>-1/10 (-1/10; 1/5) a (-1/10; 1/5) x=(5a-1) /3 x=-1-5aa>1/5x=5a-1x=(5a-1) /3 x=-1-5a